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23 July, 03:21

If f (z) = m^z - n^z, and f (1) = 2, f (2) = 8. Find f (3).

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  1. 23 July, 03:49
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    If f (z) = m^z - n^z and f (1) = 2, f (2) = 8

    then

    m - n = 2 so m = n + 2

    m^2 - n^2 = 8

    substitute m = n + 2 into m^2 - n^2 = 8

    so

    m^2 - n^2 = 8

    (n + 2) ^2 - n^2 = 8

    n^2 + 4n + 4 - n^2 = 8

    4n = 4

    n = 1

    m = n + 2 = 1 + 2 = 3

    so f (z) = 3^z - 1^z

    if z = 1 the f (1) = 3^1 - 1^1 = 2

    if z = 2 the f (2) = 3^2 - 1^2 = 9 - 1 = 8

    if z = 3 the f (3) = 3^3 - 1^2 = 27 - 1 = 26

    answer

    f (3) = 26
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