There is a rectangular section of his yard. the perimeter of the section is 27 feet and the are is 35 square feet find the length and width of the section. p=2 (L+W) if the perimeter is 27 feet solve for W. The equation for area is A=LW, substitute the expression you found for W in part 1 into the area equation. Then, if the area is equal to 35 square feet write the equation in standard form with a, b, and c as whole numbers.

Question

Hank

Mathematics

27 March, 20:13

There is a rectangular section of his yard. the perimeter of the section is 27 feet and the are is 35 square feet find the length and width of the section. p=2 (L+W) if the perimeter is 27 feet solve for W. The equation for area is A=LW, substitute the expression you found for W in part 1 into the area equation. Then, if the area is equal to 35 square feet write the equation in standard form with a, b, and c as whole numbers.

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Answers (1)

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Skyla Hull · Answer 1

2L^2 - 27L + 70 = 0.

Step-by-step explanation:

p = 2 (L + W)

27 = 2L + 2W

2W = 27 - 2L

W = (27 - 2L) / 2

Substitute for W in the area equation:

A = LW

35 = (27 - 2L) * L / 2

L (27 - 2L) = 70

-2L^2 + 27L - 70 = 0 Multiply through by - 1:

2L^2 - 27L + 70 = 0