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15 November, 23:30

Complete by solving the square

2x^2-3x-5=0

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Answers (2)
  1. 15 November, 23:41
    0
    Simplify the equation into a proper form to complete the square.

    2 x^2 - 3x=5

    Divide each term in the equation by 2

    x^2 - 3x / 2 = 5/2

    To create a trinomial square on the left-hand side of the equation, find a value that is equal to the square of half of b, the coefficient of x.

    (b/2) ^2 = ( - 3/4) ^2

    Now add the term to each side of the equation.

    x^2 - 3x / 2 + ( - 3/4) ^2 = 5/2 + ( - 3/4) ^2

    Simplify the equation.

    x/2 - 3x / 2 + 9/16 = 49/16

    Factor the perfect trinomial square into (x - 3/4) ^2.

    (x - 3/4) ^2 = 49/16

    Solve the equation for x.

    x = 5/2, - 1
  2. 15 November, 23:48
    0
    Ax² + bx + c = 0

    2x² - 3x - 5 = 0

    2x² + (-3x) + (-5) = 0

    x = - b + √b² - 4ac

    2a

    x = - (-3) + √ (-5) ² - 4 (2) (-5)

    2 (2)

    x = 3 + √25 + 40

    4

    x = 3 + √65

    4

    x = 3 + 8.062257748

    4

    x = 3 + 8.062257748 x = 3 - 8.062257748

    4 4

    x = 11.8062257748 x = - 5.062257748

    4 4

    x = 2.765564437 x = - 1.265564437
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