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5 October, 08:12

A postmix beverage machine is adjusted to release a certain amount of syrup into a chamber where it is mixed with carbonated water. A random sample of 25 beverages was found to have a mean syrup content of fluid ounces and the sample standard deviation is fluid ounces. Find a 95% two-sided confidence interval on the mean volume of syrup dispensed. Assume the population is approximately normally distributed.

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  1. 5 October, 08:17
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    You can be 95% confident that the population mean (μ) falls between 0.5837 and 1.3363.

    Step-by-step explanation:

    Calculation

    M = 0.96

    Z = 1.96

    sM = √ (0.96) ^2/25) = 0.19

    μ = M ± Z (sM)

    μ = 0.96 ± 1.96*0.19

    μ = 0.96 ± 0.3763

    Result

    M = 0.96, 95% CI [0.5837, 1.3363].

    You can be 95% confident that the population mean (μ) falls between 0.5837 and 1.3363.
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