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21 November, 04:20

If Johnny takes a rope with the length of x^2+2x-5/6x-2 and cuts of 3x-2/2, how much of the rope is left (In feet) ?

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  1. 21 November, 04:29
    0
    If you meant ...

    (x^2+2x-5) / (6x-2) - (3x-2) / 2

    You need a common denominator of 2 (6x-2) = (12x-4)

    (2x^2+4x-10 - (3x-2) (6x-2)) / (12x-4)

    (2x^2+4x-10-18x+6x+12x-4) / (12x-4)

    (2x^2-8x-14) / (12x-4)

    (x^2-4x-7) / (6x-2)
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