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28 August, 19:53

The length of a rectangle is 5 yd longer than its width.

If the perimeter of the rectangle is 30 yd, find its area,

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  1. 28 August, 20:07
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    Area of the rectangle is 36 yd²

    Step-by-step explanation:

    Step 1: Let width of the rectangle be x yd. So, length = 5 + x. Perimeter = 30 yd.

    Perimeter = 2 (length + width)

    30 = 2 (x + 5 + x)

    30 = 10 + 4x

    4x = 20

    x = 4

    ∴ 5 + x = 9

    ⇒ Length = 9 yd and width = 4 yd

    Step 2: Find area

    Area = length * *width

    = 9 * 4 = 36 yd²
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