Which equation could be used to find the length of the hypotenuse?

6^2+11^2=c^2 6^2+c^2=11^2 c^2-6^2=11^2. 11^2-6^2=c^2

6² + 11² = c²

Step-by-step explanation:

If we consider a right triangle Δ ABC, whose side AB and side BC are the two perpendicular legs, then AC is considered to be the hypotenuse.

Now, if the length of one leg AB is to be 6 units and the length of the other leg BC is to be 11 units.

Then the length of the hypotenuse, c is given by

AC² = AB² + BC² {Applying Pythagoras Theorem}

⇒ c² = 6² + 11²

⇒ 6² + 11² = c² (Answer)

In a shorter explanation its A on edgeniuty