5 red marbles 3 green Marbles and 2 blue marbles are placed in a jar what is the probability of selecting a red marble and then another red marble given the first marble is not returned to the drawer after it is drawn?

A. 1/5

B. 2/9

C. 4/45

D. 2/15

Ah, probability. So remember that for this problem, you're looking for the chance that you'll draw a red marble out of the total mix.

For the first marble, you have a 5/10 chance that you'll get a red marble (you have 5 red marbles and 10 marbles total). Now, for the second marble, since you don't return the first marble to the drawer, you only have 4 red marbles and 9 marbles in total left, so a 4/9 chance.

Multiply 5/10 by 4/9 to get your probability!

(5/10) * (4/9) = 20/90 which reduces to 2/9 which is B