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13 December, 09:47

Margo has 40 milliliters of 25% soultion how many milliliters of 60% soultin should she add to obtain the required 30% solution

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  1. 13 December, 09:51
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    Using mixture formula:

    Let volume be v, % be p

    1 should be the first mixture, 2 should be the second mixture, 3 should be the final mixture.

    p₁v₁ + p₂v₂ = p₃v₃

    p₁ = 25%, v₁ = 40 p₂ = 60%, v₂ = ? p₃ = 30%, v₃ = ?

    Let v₂ = x, v₃ = total volumes = v₁ + v₂ = (40 + x)

    Using:

    p₁v₁ + p₂v₂ = p₃v₃

    25*40 + 60*x = 30 * (40 + x)

    1000 + 60x = 1200 + 30x

    60x - 30x = 1200 - 1000

    30x = 200

    x = 200/30

    x = 20/3

    Recall x = v₂, so she has to add 20/3 milliters of the 60% solution in order to obtain 30% solution.

    I hope this explains it.
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