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Karina Gordon
Mathematics
22 June, 01:18
F (x) = x^2-8x+16 x and y intercepts and vertex
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Keith Richmond
22 June, 01:46
0
So in graphing form F (x) = y so
y=x^2-8x+16
so x intercept is when the line passes through the x axis or when y=0
y intercept is when the line passes throught the y axis or when x=0
x intercept
0=x^2-8x+16
factor
what 2 number multiply to 16 and add to get - 8
the numbers are - 4 an d - 4
0 = (x-4) (x-4)
set them to zero
x-4=0
add 4
x=4
x intercept=4 or (4,0)
y intercept
y=x^2-8x+16
x=0
y=0^2-8 (0) + 16
y=0+16
y=16
y intercept=16 or (0,16)
x intercept is 4 (4,0)
y intercetp is 16 (0,16)
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