How do I solve this?

3x-y=2 and 6x+3y=14 as a system of linear equations

Problem: Solve 3x - y = 2 and 6x + 3y = 14

Steps:I will try to solve your system of equations. 3x - y = 2; 6x + 3y = 14 Step:

Solve 3x - y = 2 for y : 3x - y + - 3x = 2 + - 3x (

Add - 3x to both sides) - y = - 3x + 2 - y - 1 = - 3x + 2 - 1 (Divide both sides by - 1) y = 3x - 2

Step: Substitute (3x - 2) for y in 6x + 3y = 14 : 6x + 3y = 14 6x + 3 (3x - 2) = 14 15x - 6 = 14 (Simplify both sides of the equation) 15x - 6 + 6 = 14+6 (Add 6 to both sides) 15x = 20 15x 15 = 2015 (Divide both sides by 15) x = 43

Step: Substitute (43) for x in y = 3x - 2 : y = 3x - 2 y = 3 (43) - 2 y=2

(Simplify both sides of the equation)

Answer: y = 2 and x = 4 3

For this, you want to eliminate one variable (get a solution for one of them). The easiest way for this specific problem would be to remove the variable y first. Take the equation 3x-y=2 and multiply everything by 3. Now you have 9x-3y=6. The y's in each equation cancel out leaving you with the x's and the integer. Add both of these together and you get 9x = 18. x = 2. Now substitute 2 in for x in either equation and solve for y.