Not including four play in games, there are 64 teams in the tournament. once a team loses one game they are eliminated. how many games would have been played if each team had to play every other team once?

Question

Josephine Hodge

Mathematics

7 December, 02:22

Not including four play in games, there are 64 teams in the tournament. once a team loses one game they are eliminated. how many games would have been played if each team had to play every other team once?

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Answers (1)

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Marcelo Burton · Answer 1

Every time teams play with each other (assuming there are no draws) half of them win

and the others get eliminated so

64:2=32 32 games played and 32 teams eliminated

32:2=16 16 games played and 16 teams eliminated

16:2=8 the same goes here

8:2=4 and here

4:2=2.

2:2=1.

32+16+8+4+2+1=63 games