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21 January, 12:33

Solve this system of equations using substitution. Put your answer in ordered pair form, (x, y).3x + 2y = 2 - 2x + y = 8

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  1. 21 January, 12:48
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    -2x + y = 8

    y = 2x + 8

    now sub in 2x + 8 for y in the other equation

    3x + 2y = 2

    3x + 2 (2x + 8) = 2 ... distribute the 2 thru the parenthesis

    3x + 4x + 16 = 2

    7x = 2 - 16

    7x = - 14

    x = - 14/7

    x = - 2

    now sub - 2 in for x in either equation to find y

    -2x + y = 8

    -2 (-2) + y = 8

    4 + y = 8

    y = 8 - 4

    y = 4

    solution is : (-2,4)
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