A quarterback throws a football to a teammate. The football is 6.5ft above the ground when it leaves the quarterback's hand. His teammate catches it 3.5s later, at a height above the ground of 5 ft.

Projectile motion formula

h (t) = - 16t2 + vt + h0

h0 = 6.5

v = ?

h = 5 when t = 3.5

Question

Ella Frank

Mathematics

13 September, 15:07

A quarterback throws a football to a teammate. The football is 6.5ft above the ground when it leaves the quarterback's hand. His teammate catches it 3.5s later, at a height above the ground of 5 ft.

Projectile motion formula

h (t) = - 16t2 + vt + h0

h0 = 6.5

v = ?

h = 5 when t = 3.5

+1

Answers (1)

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Corinne Key · Answer 1

You fill in the formula with the info they give you and solve for v:

5 = - 16 (3.5) ^2 + 3.5v + 6.5 That simplifies to 5 = - 196 + 3.5v + 6.5 Now simplify further by combining like terms and getting the v term by itself on one side. 194.5 = 3.5v Now divide both sides by 3.5 to get a velocity of 55.57 feet per second.

A quarterback throws a football to a teammate. The football is 6.5ft above the ground when it leaves the quarterback's hand. His teammate catches it 3.5s later, at a height above the ground of 5 ft.Projectile motion formulah (t) = - 16t2 + vt + h0h0 = 6.5v = ?h = 5 when t = 3.5

A quarterback throws a football to a teammate. The football is 6.5ft above the ground when it leaves the quarterback's hand. His teammate catches it 3.5s later, at a height above the ground of 5 ft.

Projectile motion formula

h (t) = - 16t2 + vt + h0

h0 = 6.5

v = ?

h = 5 when t = 3.5