A mixture of

12%

disinfectant solution is to be made from

10%

and

17%

disinfectant solution. How much of each solution should be used if

28

gallons of the

12%

solution are needed?

Question

Laurel Knapp

Mathematics

5 July, 21:39

A mixture of

12%

disinfectant solution is to be made from

10%

and

17%

disinfectant solution. How much of each solution should be used if

28

gallons of the

12%

solution are needed?

+5

Answers (1)

Know the Answer?

Sadie · Answer 1

Set up a system of 2 equations.

Gallon equation:

x+y = 28

Solution equation:

10x + 17y = (28) (12)

Solve with substitution:

y = 28-x (From 1st equation)

(Sub into 2nd equation)

10x + 17 (28-x) = 336

10x + 476 - 17x = 336

-7x = - 140

x = 20

y = 28-20 = 8

Therefore the solution is (20,8)

You need 20 gal of 10% solution mixed with 8 gal of 17% solution to obtain 28 gal of 12% solution.

A mixture of12%disinfectant solution is to be made from10%and17%disinfectant solution. How much of each solution should be used if28gallons of the12%solution are needed?

A mixture of

12%

disinfectant solution is to be made from

10%

and

17%

disinfectant solution. How much of each solution should be used if

28

gallons of the

12%

solution are needed?