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29 June, 08:35

Evaluate the integral: integral of t sinh mt dt

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  1. 29 June, 08:48
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    Integrate by parts

    f = t, df = dt,

    dg = sinh (mt) dt

    g = cosh (mt) / m

    put them together

    tcosh (mt) / m - / m * ∫cosh (mt) dt

    u = mt, du = mdt

    tcosh (mt) / m - / m^2 * ∫cosh (u) dt

    integral of cosh (u) = sinh (u)

    tcosh (mt) / m - sinh (u) / m^2 + c1

    substitute back in the u (mt)

    tcosh (mt) / m - sinh (mt) / m^2 + c1

    You can simplify this

    ((mt*cosh (mt) - sinh (mt))) / m^2
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