For what value of x will sin x = cos 19°, given 0°< x < 90°?

Sin x = cos 19°; 0° < x < 90°

cos is the complementary of sine. This means that the value of x in sin x and the value of 19° in cos 19° adds up to 90°

x + 19° = 90°

x = 90° - 19°

x = 71°

sin 71° = cos 19°

0.9455 = 0.9455

The value of x is 71°