A rectangle has a length of x inches and a width 2 inches less than the length. If the dimensions were tripled what would be the area of the new rectangle in terms o x

Originally we have

length = x

width = x-2

since the width is 2 inches smaller than the length

now let's triple each dimension. Multiply the expressions by 3 to get

new length = 3*x

new width = 3 * (x-2) = 3x-6

Now onto the area

area = (length) * (width)

area = (3x) * (3x-6)

area = 3x*3x-3x*6

area = 9x^2 - 18x

So the new larger rectangle has area of 9x^2-18x