If ab = 8 and a^+b^2=16, then what is the value of (a+b) ^2?

Question

Abbie Sosa

Mathematics

19 March, 15:18

If ab = 8 and a^+b^2=16, then what is the value of (a+b) ^2?

+3

Answers (2)

Know the Answer?

Rodolfo Conway · Answer 1

32

Step-by-step explanation:

(a+b) ^2

This is the product of squares and equals

(a+b) (a+b) = a^2 + 2ab + b^2

Rearranging the terms

a^2 + b^2 + 2*ab

We know a^2+b^2 = 16 and ab = 9

16 + 2 (8)

16+16

32

Daniel Bush · Answer 2

32

Step-by-step explanation:

(a + b) ² = a² + 2ab + b²

= (a² + b²) + 2 (ab)

= 16 + 2 (8)

= 32