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19 March, 15:18

If ab = 8 and a^+b^2=16, then what is the value of (a+b) ^2?

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Answers (2)
  1. 19 March, 15:31
    0
    32

    Step-by-step explanation:

    (a+b) ^2

    This is the product of squares and equals

    (a+b) (a+b) = a^2 + 2ab + b^2

    Rearranging the terms

    a^2 + b^2 + 2*ab

    We know a^2+b^2 = 16 and ab = 9

    16 + 2 (8)

    16+16

    32
  2. 19 March, 15:37
    0
    32

    Step-by-step explanation:

    (a + b) ² = a² + 2ab + b²

    = (a² + b²) + 2 (ab)

    = 16 + 2 (8)

    = 32
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