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12 May, 21:06

The lead of a screw is the distance that the screw advances in a straight line when the screw is turned 1 complete turn. If the screw is 2 1/2 inches long and has a lead of 1/8 inch, how many complete turns would get it all the way into a piece of wood?

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  1. 12 May, 21:34
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    Based on the given problem the lead is 1/8 inch

    so with one turn the screw advances 1/8 of an inch

    to find the number of turns needed you would need to divide the length (2 1/2) by the lead (1/8)

    first step is to turn 2 1/2 into an improper fraction by multiplying the whole number by the denominator and adding the numerator and using that number as the new numerator:

    2 1/2 = = 2*2 = 4 + 1 = 5/2

    now divide 5/2 x 1/8

    to divide 2 fractions, flip the second one over and then multiply straight across:

    5/2 / 1/8 becomes 5/2 x 8/1

    8x5 = 40 and 2x1 = 2 so you would have 40/2 which reduces to 20

    this means it would take 20 complete turns
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