The crew on fishing boat caught four fish weighing a total of 1092 pounds. The tarpon weighed twice as much as the amberjack and the white marlin weighed twice as much as the the tarpon. The weight of the tuna was 5 times the weight the amberjack. How much did each fish weigh?

Question

Sammy Maldonado

Mathematics

5 January, 11:53

The crew on fishing boat caught four fish weighing a total of 1092 pounds. The tarpon weighed twice as much as the amberjack and the white marlin weighed twice as much as the the tarpon. The weight of the tuna was 5 times the weight the amberjack. How much did each fish weigh?

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Answers (2)

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Jack Haynes · Answer 1

X = weight of amberjack

2x = weight of tarpon

4x = weight of marlin

5x = weight of tuna

x + 2x + 4x + 5x = 1092

12x=1092

x = 91

Amberjack weighs 91 pounds

Tarpon = 2 x 91 = 182 pounds

Marlin = 4 x 91 = 364 pounds

Tuna = 5 x 91 = 455 pounds

Montgomery · Answer 2

Ta = tarpon

am = amberjack

wm = white marlin

tu = tuna

ta + am + wm + tu = 1092

ta = 2 * am

wm = 2 * ta = 4 * am

tu = 5 * am

2 * am + 4 * am + 5 * am + am = 12 am = 1092

am = 91

ta = 2 * 91 = 182

etc ...