A square has a perimeter of 36 units. One vertex of the square is located at (3, 5) on the coordinate grid. What could be the x - and y-coordinates of another vertex of the square?

Answer with explanation:

Perimeter of Square = 36 units

Also, Perimeter of Square = 4 * Side

→4 * Side=36

Dividing both sides by, 4 we get

Side of Square = 9 units

Length of Diagonal of square having side a, = √2 a

Length of Diagonal of Square having side, 9 units = 9 √2 units

One Vertex of the Square = (3,5)

As, All Interior Angles of Square measures 90°.

So, Other vertices of Square will be, (3,-4), (-6,-4) and (-6,5).

(3,-5)