Find the center and the radius of the circle with the equation:
x^2 + 6x + y^2 + 4y + 12 = 0
a.
center: (3, 2)
radius: 1
c.
center: (6, 4)
radius: 12
b.
center: (-3, - 2)
radius: 1
d.
center: (-6, - 4)
radius: 12
+2
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Home » Mathematics » Find the center and the radius of the circle with the equation: x^2 + 6x + y^2 + 4y + 12 = 0 a. center: (3, 2) radius: 1 c. center: (6, 4) radius: 12 b. center: (-3, - 2) radius: 1 d. center: (-6, - 4) radius: 12