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11 November, 13:57

How do you solve the linear equations y=2x-3 and 4y=2x+8

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  1. 11 November, 14:06
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    Subtract the first equation from the second to get:

    4y-y=2x-2x+8+3

    Simplifying, we see that 3y=11, so y=11/3. Substituting this into the first equation, we have:

    11/3=2x-3

    Adding 3, we see that 2x=20/3, so x=10/3.
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