Ask Question
19 October, 13:14

A tour boat on a river travled 40 miles downstream in 4 hours. The return trip against the current took 5 hours.

What was the rate of the current?

A) 2.0 mph

B) 1.5 mph

C) 0.5 mph

D) 1.0 mph

+3
Answers (1)
  1. 19 October, 13:26
    0
    D) 1.0 mph

    Step-by-step explanation:

    Own speed the boat = x

    rate (speed) of the current = a

    Speed of the boat downstream = (x + a)

    Speed of the boat upstream = (x - a)

    Speed of the boat downstream = 40 mi/4 h = 10 mi/h

    Speed of the boat upstream = distance/time = 40 mi / 5 h = 8 mi/h

    x + a = 10

    x - a = 8

    2x = 18

    x = 9

    x + a = 10

    9 + a = 10

    a = 1 mi/h
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “A tour boat on a river travled 40 miles downstream in 4 hours. The return trip against the current took 5 hours. What was the rate of the ...” in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers