The sum of three numbers is 142. The first number is 8 less than the second. The third number is 4 times the second. What are the numbers?

X = 1st number, y = 2nd number, z = 3rd number

x + y + z = 142

x = y - 8

z = 4y

y - 8 + y + 4y = 142

6y - 8 = 142

6y = 142 + 8

6y = 150

y = 150/6

y = 25 < = = = the 2nd number

x = y - 8

x = 25 - 8

x = 17 < = = the 1st number

z = 4y

z = 4 (25)

z = 100 < = = = 3rd number