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21 April, 18:44

f (x) = (x - 3) (x + 3) [x - (2 - i) ][x - (2 + i) ] The function has real roots and imaginary roots.

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  1. 21 April, 19:00
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    The real roots are 3 and - 3.

    Imaginary roots:-

    x - (2 - i) = 0

    x = 2 - i is one imaginary root and the other is 2 + i
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