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8 June, 05:27

If k is constant, what is the value of k that hte polynomial k^2x^3-6kx 9 is divisible by x-1

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  1. 8 June, 05:29
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    Solve k²-6k+9 = (k-3) ²=0, so k=3. The polynomial becomes 9x³-18x+9=9 (x³-2x+1) = 9 (x-1) (x²+x-1).
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