What functions have real zeros at 1 and 4

y=a (x^2-5x+4)

Step-by-step explanation:

I mean there are a bunch of answers. to figure it out, you can use the formula where you have solved the zeroes in terms of x.

y = (x-1) (x-4)

y=x^2-5x+4

Now if you add any a value to this function, your function will stretch or compress accordingly

y=a (x^2-5x+4)

So there isn't a single correct answer, but if you're looking for a bunch, then just replace the a value with whatever value you want, you'll still get the same answer since they're all proportional to one another.