Two consecutive even integers have a product that is 1848. What are the integers?

Question

Nikolai Myers

Mathematics

23 April, 00:13

Two consecutive even integers have a product that is 1848. What are the integers?

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Patches · Answer 1

Factors of 1848=1, 2, 3, 4, 6, 7, 8, 11, 12, 14, 21, 22, 24, 28, 33, 42, 44, 56, 66, 77, 84, 88, 132, 154, 168, 231, 264, 308, 462, 616, 924, 1848 X (x+2) = 1848 X^2+2x=1848 X^2+2-1848=0 (X+44) (x-42) = 0 X+44=0 X=-44 X-42=0 X=42 So x=-44,42