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10 January, 15:13

A force of 6 lb is required to hold a spring stretched 8 in. beyond its natural length. How much work W is done in stretching it from its natural length to 11 in. beyond its natural length?

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  1. 10 January, 15:43
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    Work done is 1.02J

    Step-by-step explanation:

    Work (W) done in stretching a spring = 1/2Fe

    F (force) = 6 lb = 6*4.4482N = 26.6892N

    e (extension) = 11in - 8in = 3in = 3*0.0254m = 0.0762m

    W = 1/2 * 26.6892 * 0.0762 = 1.02J
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