At 9:00am cyclist A off on a trail at an average speed of 16km/h. At 10:00am cyclist B off from the same place, in the same direction at an average speed of 24km/h. At what time will cyclist Bcatch up with cyclistA

Question

Taniya Howard

Mathematics

27 January, 17:11

At 9:00am cyclist A off on a trail at an average speed of 16km/h. At 10:00am cyclist B off from the same place, in the same direction at an average speed of 24km/h. At what time will cyclist Bcatch up with cyclistA

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Answers (1)

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Thalia · Answer 1

noon

Step-by-step explanation:

Cyclist B gains on Cyclist A at the rate of 24 - 16 = 8 km/hour. Cyclist A has a 1-hour, or 16 km, head start. Cyclist B will make up that difference in 2 hours, at 12:00 pm (noon).