Ask Question
29 March, 08:08

The length of a rectangle is 3 cm less than twice the width. if the area of the rectangle is 54 cm2, what is the width of the rectangle

+1
Answers (1)
  1. 29 March, 08:17
    0
    Make an equation system based on the problem

    "The length of a rectangle is 3 cm less than twice the width" could be written as

    ∴ l = 2w - 3 (first equation)

    "The area is 54" could be written as

    ∴ l * w = 54 (second equation)

    Substitute (2w - 3) into l in the second equation

    l * w = 54

    (2w - 3) * w = 54

    2w² - 3w = 54

    2w² - 3w - 54 = 0

    (2w + 9) (w - 6) = 0

    The zeros of the equation

    2w + 9 = 0 or w - 6 = 0

    w = - 9/2 or w = 6

    Because the width couldn't be negative, - 9/2 is excluded from the solution. The width of the rectangle is 6 cm
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “The length of a rectangle is 3 cm less than twice the width. if the area of the rectangle is 54 cm2, what is the width of the rectangle ...” in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers