Maya will rent a car for the weekend. she can choose one of two plans. the first plan had an initial fee of $59.96 and costs an additional $0.11 per mile driven the second plan has an initial fee of $49.96 and cost an additional $0.13 per mile driven. how many miles would ma a need to drive for the two plans to cost the same?

Question

Zane

Mathematics

1 May, 19:52

Maya will rent a car for the weekend. she can choose one of two plans. the first plan had an initial fee of $59.96 and costs an additional $0.11 per mile driven the second plan has an initial fee of $49.96 and cost an additional $0.13 per mile driven. how many miles would ma a need to drive for the two plans to cost the same?

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Cody Gutierrez · Answer 1

Hello there! To figure out the answer to this problem, we can write and solve an equation. Set it up like this:

59.96 + 0.11m = 49.96 + 0.13m

This is because the initial fees are a fixed priced, and you have to pay a certain amount per mile. First, let's subtract 0.11m from both sides. That will get us 59.96 = 49.96 + 0.02m. Next, let's subtract 49.96 from both sides. That gets us 10 = 0.02m. Now, divide each side by 0.02 to isolate the m. 10/0.02 is 500. Let's check that value and see if it works. 500 * 0.11 is 55. 55 + 59.96 is 114.96. 0.13 * 55 is 65. 65 + 49.96 is 114.96. 114.96 = 114.96. There. m = 500. Maya would have to drive 500 miles in order for both plans to cost the same.