Find the samllest value of K when:

280k is a perfect square

882 is a cube

280 = 7 x 2^3 x 5

882 = 7^2 x 2 x 3^2

For 280k to be perfect square, their powers need to be even

For 882 to be a cube, their powers need to be in multiple of 3,

To satisfy both parties,

K = 7 x 2^5 x 3^4 x 5^3 = 2268000