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Sharon Barajas
Mathematics
21 December, 04:03
Find the samllest value of K when:
280k is a perfect square
882 is a cube
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Nyasia Woodard
21 December, 04:22
0
280 = 7 x 2^3 x 5
882 = 7^2 x 2 x 3^2
For 280k to be perfect square, their powers need to be even
For 882 to be a cube, their powers need to be in multiple of 3,
To satisfy both parties,
K = 7 x 2^5 x 3^4 x 5^3 = 2268000
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