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13 September, 10:25

Eight percent of all college graduates hired by companies stay with the same company for more than five years. The probability that in a random sample of 12 such college graduates hired recently by companies, exactly two will stay with the same company for more than five years is

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  1. 13 September, 10:54
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    0.1835

    Step-by-step explanation:

    This question can be solved by way of binomial distribution.

    Let's have the probability of success as p which is the probability that they stay with the company for more than five years;

    p = 8/100 = 0.08

    probability of failure, meaning not staying is q = 1-p = 1-0.08 = 0.92

    Now let's write the expression for the binomial distribution. That would be;

    probability = 12C2 * 0.08^2 * 0.92^10

    = 0.1835
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