Ask Question
4 July, 21:36

Find all numbers such that the square of the number is 48 more than double the number. If you find more than one, then list all the numbers you find in increasing order, separated by commas.?

+1
Answers (1)
  1. 4 July, 21:51
    0
    -6, 8

    Step-by-step explanation:

    Let the numbers be represented by y

    Square of y = y^2

    Double y = 2 * y = 2y

    Square of the number is 48 more than double the number is written mathematically as

    y^2 = 2y + 48

    y^2 - 2y - 48 = 0

    This is a quadratic equation and can be solved by method of factorisation

    y^2 - 2y - 48 = 0

    y^2 + 6y - 8y - 48 = 0

    (y^2 + 6y) - (8y - 48) = 0

    y (y + 6) - 8 (y + 6) = 0

    (y + 6) (y - 8) = 0

    y = - 6, 8

    The numbers are - 6, 8
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “Find all numbers such that the square of the number is 48 more than double the number. If you find more than one, then list all the numbers ...” in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers