Use substitution to solve each system.

-3y = - 2x - 1

y = x - 1

-3y = - 2x - 1

y = x - 1

Substitute the y in the first problem for it's equivalent (the second problem):

-3 (x - 1) = - 2x - 1

Distribute

-3x + 3 = - 2x - 1

Add 2x to both sides

-1 x + 3 = - 1

Subtract 3 from both sides

-1x = - 4

x = 4

Now put that back into one of the original equations:

y = x - 1

y = 4 - 1

y = 3

So, x is 4 and y is 3.

-3y = - 2x - 1

-3 (x - 1) = - 2x - 1

-3x + 3 = - 2x - 1

-x + 3 = - 1

-x = - 4

x = 4

y = x - 1

y = (4) - 1

y = 3

(4,3) is your solution