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17 January, 01:02

Your family orders delivery from a local restaurant

for dinner. There are 6 people in your family.

Some order the chicken dinner for $14 and some

order the steak dinner for $17. If the total bill was

$99, how many people ordered each dinner?

Let x = chicken

x + y = 6

Let y = steak

14x + 17 y = 99

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Answers (1)
  1. 17 January, 01:24
    0
    The number of people who ordered steak dinner is 5

    The number of people who ordered chicken dinner is 2

    Step-by-step explanation:

    Given as:

    The total number of people went for the dinner = 7

    The total bill price for the dinner = $ 109

    The price for the chicken dinner = $ 12

    The price for the steak dinner = $ 17

    Let The number of people who ordered chicken dinner = c

    And The number of people who ordered steak dinner = s

    Now, According to question

    The total number of people went for the dinner = The number of people who ordered chicken dinner + The number of people who ordered steak dinner

    Or, c + s = 7

    And The total bill price for the dinner = The price for the chicken dinner * The number of people who ordered chicken dinner + The price for the steak dinner * The number of people who ordered steak dinner

    Or, $ 12 * c + $ 17 * s = $ 109

    Now, solving the equations

    $ 12 * (c + s) = $ 12 * 7

    Or, $ 12 * c + $ 12 * s = $ 84

    Or, ($ 12 * c + $ 17 * s) - ($ 12 * c + $ 12 * s) = $ 109 - $ 84

    Or, ($ 12 * c - $ 12 * c) + ($ 17 * s - $ 12 * s) = $ 25

    Or, (0) + ($ 5 s) = $ 25

    ∴ s = / frac{25}{5}

    I. e s = 5

    So, The number of people who ordered steak dinner = s = 5

    Put the value og s in Eq A

    ∵, c + s = 7

    or, c = 7 - s

    Or, c = 7 - 5

    I. e c = 2

    So, The number of people who ordered chicken dinner = c = 2

    Hence The number of people who ordered steak dinner is 5

    And The number of people who ordered chicken dinner is 2 Answer
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