The Shady Farm Milk Company can process milk at a fixed rate of 7500 gallons/hour. The company's clients request 100,000 gallons of milk over the course of one day. This demand is spread out uniformly from 8 a. m. to 6 p. m. The company starts producing at 8 a. m. and continues to work until all of the demand has been satisfied. At noon, how many gallons of milk are in the queue to be processed?

Question

Monserrat Vasquez

Mathematics

13 January, 04:36

The Shady Farm Milk Company can process milk at a fixed rate of 7500 gallons/hour. The company's clients request 100,000 gallons of milk over the course of one day. This demand is spread out uniformly from 8 a. m. to 6 p. m. The company starts producing at 8 a. m. and continues to work until all of the demand has been satisfied. At noon, how many gallons of milk are in the queue to be processed?

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Kevin Hines · Answer 1

70000 gallons

Step-by-step explanation:

The total time between 8 a. m. to 6 p. m is 10 hours. The company starts producing at 8 am, therefore the time from 8 am to noon (that is 12 p. m) is 4 hours.

Since clients demand 100,000 gallons of milk over the course of one day, the demand of milk per hour = total demand per day / total time per day

Demand per hour = 100000 gallons / 10 hours = 10000 gallons per hour

Since the milk is processed at a fixed rate of 7500 gallons/hour, At noon the amount of of milk produced = 7500 gallons/hour * 4 hours = 30000 gallons.

The gallons of milk are in the queue to be processed at noon = 100000 gallons - 30000 gallons = 70000 gallons