Find the number of real number solutions for the equation. x² + 26 = 0 ☺☻

A.) Can not be determined from the graph

B.) 2

C.) 0

D.) 1

Question

Caitlin Park

Mathematics

16 July, 19:33

Find the number of real number solutions for the equation. x² + 26 = 0 ☺☻

A.) Can not be determined from the graph

B.) 2

C.) 0

D.) 1

+1

Answers (1)

Know the Answer?

Karlee Arroyo · Answer 1

X^2+26=0

So x^2=-26

now x=squareroot (-26)

Since the value of x is squareroot (-26) which is not a real number and is a imaginary number so roots does not exist for this equation.

So option c 0 real roots is correct

Find the number of real number solutions for the equation. x² + 26 = 0 ☺☻A.) Can not be determined from the graphB.) 2C.) 0D.) 1

Find the number of real number solutions for the equation. x² + 26 = 0 ☺☻

A.) Can not be determined from the graph

B.) 2

C.) 0

D.) 1