Find the number of real number solutions for the equation. x² + 26 = 0 ☺☻

A.) Can not be determined from the graph

B.) 2

C.) 0

D.) 1

X^2+26=0

So x^2=-26

now x=squareroot (-26)

Since the value of x is squareroot (-26) which is not a real number and is a imaginary number so roots does not exist for this equation.

So option c 0 real roots is correct