How many and what type of solution (s) does the equation have?

2w² + 50 = 20w

A. 2 irrational solutions

B. 1 rational solution

C. 2 rational solutions

D. 2 non-real solutions

Let's use the quadratic formula:

2w² - 20w + 50 = 0

a = 2 b = - 20 c = 50

x = - b + - sq root (b^2 - 4*a*c) / 2*a

x = - - 20 + - sq root (400 - 4*2*50) / 4

x = 20 + - sq root (400 - 4*2*50) / 4

x = 20 + - sq root (0) / 4

x = 20 / 4 = 5

I'd say it has one rational solution.

It does NOT have 2 solutions because the "plus / minus" section = 0.