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19 August, 10:49

Write thw equation of the line that it is perpendicular to y=7x-3 and passes through the origin

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  1. 19 August, 11:14
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    Equation of the line that it is perpendicular to y=7x-3 and passes through the origin is given by 7y + x = 0

    Explanation:

    We have equation of line, y = 7x - 3, comparing it with y = mx + c

    So slope of line, m = 7

    We know that the product of slopes of perpendicular lines = - 1

    So m*Slope of perpendicular line = - 1

    7 * slope of perpendicular line = - 1

    slope of perpendicular line = - 1/7

    Given that the perpendicular line passes through origin (0,) 0)

    We also know that equation of a line passing though origin is given by the expression, y = mx

    Here m = - 1/7

    So equation of perpendicular line, y = - x/7

    or 7y + x = 0

    Equation of the line that it is perpendicular to y=7x-3 and passes through the origin is given by 7y + x = 0
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