Find four consecutive integers if the sum of the second and fourth is 48

Step-by-step explanation:

Let the four consecutive integers be

x, x+1, x+2, x+3

According to the given statement the sum of 2nd and 4th is 48 so,

x+1+x+3=48

2x+4=48

2x=44

x=22

So the four consecutive integers are

x=22,

x+1=23,

x+2=24,

x+3=25