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Watson
Mathematics
8 August, 04:21
Factor the quadratic equations W^2-W-12
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Cecelia Griffith
8 August, 04:24
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Given
W^2-W-12 = w^2+bW+c
b=-1,
c=-12
We look for m, n so that m+n=b=-1, m*n=c=-12, where m, n are integer factors of - 12.
Now enumerate all possibilities for m*n=12
m n m*n m+n
1 - 12 - 12 - 11
2 - 6 - 12 - 4
3 - 4 - 12 - 1 ... so m*n=-12, m+n=-1
The factorization is then
W^2-W-12 = (W+3) (W-4)
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