The Booster Club voted on

where they would go for their

annual trip. A majority of the

club voted to go to a baseball

game. They bought 29 tickets.

Some of the tickets cost $21

each and some cost $27 each.

The total cost of all the tickets

was $675. How many tickets

of each price did they buy?

The number of tickets purchased costing $21 each = 18

The number of tickets purchased costing $ 27 each = 11

Step-by-step explanation:

The total number of tickets purchased = 29

Here, let us assume that:

The number of tickets purchased costing $21 = m

The number of tickets purchased costing $ 27 = 29 - m

So, now the cost of m tickets costing $21 each = m x ($21) = 21 m

Also, the cost of purchasing (29-m) tickets costing $27 each

= (29-m) x $27 = 783 - 27 m

Also, the total cost of purchasing 29 tickets = $ 675

⇒ The total cost of m tickets + (29 - m) tickets = $ 675

or, 21 m + 783 - 27 m = 675

⇒ - 6 m = 675 - 783 = - 108

or, m 108/6 = 18

⇒ m = 18

Hence the number of tickets purchased costing $21 each = m = 18

The number of tickets purchased costing $ 27 each = 29 - m

= 29 - 18 = 11