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4 October, 12:39

Determine the center and radius of the following circle equation:

x ^2+y ^2 - 18x+4y+60=0

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  1. 4 October, 13:01
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    Answer:Use the quadratic 'Complete the Square' method

    Step-by-step explanation:#x^2 - 6x + y^2 - 4y = 12

    Then take 1/2 of the 'b' term for both quadratic expressions, square those values and add them to both sides.

    #x^2 - 6x + 9 + y^2 - 4y + 4 = 12 + 9 + 4

    (x - 3) ^2 + (y - 2) ^2 = 25

    Circle centered at (3,2) with radius = 5
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