1.) What is the vertex of the quadratic function y=x^2-4x-1

2.) What is the solution set for the quadratic function y=x^2-4x-21

3.) What are the solutions to the quadratic equation (x+9) (x-1) = 0

4.) What are the zeros for the quadratic function f (x) = x^2+10+25

Question

7 November, 11:49

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Answers (1)

Know the Answer?

Jerry Roy · Answer 1

1. Solve by differentiation (Derivative = 0 at the vertex)

dy/dx = 2x-4

0=2x-4

0=2 (x-2)

x=2

when x=2 y=-5

therefore vertex (2,-5)

1.) What is the vertex of the quadratic function y=x^2-4x-12.) What is the solution set for the quadratic function y=x^2-4x-213.) What are the solutions to the quadratic equation (x+9) (x-1) = 04.) What are the zeros for the quadratic function f (x) = x^2+10+25