121=3.143square root of r^2+h^2

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Lilyana Guerra

Mathematics

10 September, 12:10

121=3.143square root of r^2+h^2

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Nick Galloway · Answer 1

First, isolate. To do so, divide both sides by. Then, eliminate the radical. So, square both sides of the equation To have h^2 only at the right side, subtract both sides by r^2. And, to have h only, take the square root of both sides of equation

121=3.14*3*square root of r^2+h^2

121=3.143square root of r^2+h^2