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Jazlynn Hammond
Mathematics
16 June, 04:31
9 • 8 - 2x + x2 ≥ x3 + x2
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Annie Powers
16 June, 04:37
0
9 (8) - 2x+x^2>=x^3+x^2
-2x+72-x^3>=0
-x^3-2x+72>=0
X^3+2x-72<=0
Factor
(X-4) (x^2+4x+18) <=0
Solve for x
X<=4
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Phoenix Vaughan
16 June, 04:58
0
x² - 2x + 9 (8) ≥ x³ + x²
x² - 2x + 72 ≥ x³ + x²
- x² - x²
-x³ - 2x + 72 ≥ 0
-1 (x³) - 1 (2x) - 1 (72) ≥ 0
-1 (x³ + 2x - 72) ≥ 0
-1 - 1
x³ + 2x - 72 ≥ 0
x³ + 4x² - 4x² + 18x - 16x - 72 ≥ 0
x³ + 4x² + 18x - 4x² - 16x - 72 ≥ 0
x (x²) + x (4x) + x (18) - 4 (x²) - 4 (4x) - 4 (18) ≥ 0
x (x² + 4x + 18) - 4 (x² + 4x + 18) ≥ 0
(x - 4) (x² + 4x + 18) ≥ 0
x - 4 ≥ 0 or x² + 4x + 18 ≥ 0
+ 4 + 4 x ≥ - (4) ± √ ((4) ² - 4 (1) (18))
x ≥ 4 2 (1)
x ≥ - 4 ± √ (16 - 72)
2
x ≥ - 4 ± √ (-56)
2
x ≥ - 4 ± 2i√ (14)
2
x ≥ - 2 ± i√ (14)
x ≥ - 2 + i√ (14) or x ≥ - 2 - i√ (14)
Solution Set: {4, - 2 ± i√ (14) }
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